Contents:
Contents:
- Leftmost index value is
0. - If the element is not found, null is returned.
- For right-to-left searching, use ARRAYRIGHTINDEXOF.
- If only one element exists in the array, both functions return the same value.
- For more information, see ARRAYRIGHTINDEXOF Function.
Wrangle vs. SQL: This function is part of Wrangle, a proprietary data transformation language. Wrangle is not SQL. For more information, see Wrangle Language.
Basic Usage
Array literal reference example:
arrayindexof(["A","B","C","D"],"C")
Output: Returns the index of the element "C" in the array, which is 2 in an 0-based index.
Column reference example:
arrayindexof([myValues],myElement)
Output: Returns the index in the myValues arrays for the elements listed in the myElement column.
Syntax and Arguments
arrayindexof(array_ref,my_element)
| Argument | Required? | Data Type | Description |
|---|---|---|---|
| array_ref | Y | array or string | Name of Array column, Array literal, or function returning an Array to apply to the function |
| my_element | Y | any | The element to locate in the array |
For more information on syntax standards, see Language Documentation Syntax Notes.
array_ref
Name of the array column, array literal, or function returning an array whose element you want to locate.
- Multiple columns and wildcards are not supported.
Usage Notes:
| Required? | Data Type | Example Value |
|---|---|---|
| Yes | String (column reference or function) or array literal | myArray1 |
my_element
Element literal that you wish to locate in the array. It can be a value of any data type.
Usage Notes:
| Required? | Data Type | Example Value |
|---|---|---|
| Yes | Any | "1st"
|
Tip: For additional examples, see Common Tasks.
Examples
Example - Computing points based on position of finish
Functions:
| Item | Description |
|---|---|
| ARRAYINDEXOF Function | Computes the index at which a specified element is first found within an array. Indexing is left to right. |
| ARRAYRIGHTINDEXOF Function | Computes the index at which a specified element is first found within an array, when searching right to left. Returned value is based on left-to-right indexing. |
Source:
The following set of arrays contain results, in order, of a series of races. From this list, the goal is to generate the score for each racer according to the following scoring matrix.
| Place | Points |
|---|---|
| 1st | 30 |
| 2nd | 20 |
| 3rd | 10 |
| Last | -10 |
| Did Not Finish (DNF) | -20 |
Results:
| RaceId | RaceResults |
|---|---|
| 1 | ["racer3","racer5","racer2","racer1","racer6"] |
| 2 | ["racer6","racer4","racer2","racer1","racer3","racer5"] |
| 3 | ["racer4","racer3","racer5","racer2","racer6","racer1"] |
| 4 | ["racer1","racer2","racer3","racer5"] |
| 5 | ["racer5","racer2","racer4","racer6","racer3"] |
Transformation:
Note that the number of racers varies with each race, so determining the position of the last racer depends on the number in the event. The number of racers can be captured using the following:
| Transformation Name | New formula |
|---|---|
| Parameter: Formula type | Single row formula |
| Parameter: Formula | ARRAYLEN(RaceResults) |
| Parameter: New column name | 'countRacers' |
Create columns containing the index values for each racer. Below is the example for racer1:
| Transformation Name | New formula |
|---|---|
| Parameter: Formula type | Single row formula |
| Parameter: Formula | ARRAYINDEXOF(RaceResults, 'racer1') |
| Parameter: New column name | 'arrL-IndexRacer1' |
| Transformation Name | New formula |
|---|---|
| Parameter: Formula type | Single row formula |
| Parameter: Formula | ARRAYRIGHTINDEXOF(RaceResults, 'racer1') |
| Parameter: New column name | 'arrR-IndexRacer1' |
You can then compare the values in the two columns to determine if they are the same.
NOTE: If ARRAYINDEXOF and ARRAYRIGHTINDEXOF do not return the same value for the same inputs, then the value is not unique in the array.
Since the points awarded for 1st, 2nd, and 3rd place follow a consistent pattern, you can use the following single statement to compute points for podium finishes for racer1: computing based on the value stored for the left index value:
| Transformation Name | Conditional column |
|---|---|
| Parameter: Condition type | if...then...else |
| Parameter: If | {arrayL-IndexRacer1} < 3 |
| Parameter: Then | (3 - {arrayL-IndexRacer1}) * 10 |
| Parameter: Else | 0 |
| Parameter: New column name | 'ptsRacer1' |
The following transform then edits the ptsRacer1 to evaluate for the Did Not Finish (DNF) and last place conditions:
| Transformation Name | Edit column with formula |
|---|---|
| Parameter: Columns | ptsRacer1 |
| Parameter: Formula | IF(ISNULL({arrayL-IndexRacer1}), -20, ptsRacer1)) |
You can use the following to determine if the specified racer was last in the event:
| Transformation Name | Edit column with formula |
|---|---|
| Parameter: Columns | ptsRacer1 |
| Parameter: Formula | IF(arrR-IndexRacer1 == countRacers, -10, ptsRacer1) |
Results:
| RaceId | RaceResults | countRacers | arrR-IndexRacer1 | arrL-IndexRacer1 | ptsRacer1 |
|---|---|---|---|---|---|
| 1 | ["racer3","racer5","racer2","racer1","racer6"] | 5 | 3 | 3 | 0 |
| 2 | ["racer6","racer4","racer2","racer1","racer3","racer5"] | 6 | 3 | 3 | 0 |
| 3 | ["racer4","racer3","racer5","racer2","racer6","racer1"] | 6 | 5 | 5 | -10 |
| 4 | ["racer1","racer2","racer3","racer5"] | 4 | 0 | 0 | 20 |
| 5 | ["racer5","racer2","racer4","racer6","racer3"] | 5 | null | null | -20 |
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