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Comment: Published by Scroll Versions from space DEV and version r0761

The following example demonstrates how the exponential functions work together. These functions include the following:

Source:

rowNumX
1-2
21
30
41
52
63
74
85

Transformation:

D trans
RawWrangle true 'expX' step derive type:single value: EXP (X) as: 'expX' Formula type Single row formula Formula EXP (X) New column name New formula

D trans
RawWrangle true 'ln_expX' step derive type:single value: LN (expX) as: 'ln_expX' Formula type Single row formula Formula LN (expX) New column name New formula

D trans
RawWrangle true 'logX' step derive type:single value: LOG (X) as: 'logX' Formula type Single row formula Formula LOG (X) New column name New formula

D trans
RawWrangle true 'pow_logX' step derive type:single value: POW (10,logX) as: 'pow_logX' Formula type Single row formula Formula POW (10,logX) New column name New formula

Results:

In the following, `(null value)` indicates that a null value is generated for the computation.

rowNumXexpXln_expXlogXpow_logX
1-20.1353352832366127-2(null value)(null value)
2-10.1353352832366127-0.9999999999999998(null value)(null value)
3010(null value)0
412.718281828459045101
527.389056098930649520.301029995663981141.9999999999999998
6320.08553692318766830.477121254719662443
7454.5981500331442340.60205999132796233.999999999999999
85148.4131591025765750.69897000433601874.999999999999999