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Outdated release! Latest docs are Release 8.2: ABS Function

Computes the absolute value of a given numeric value. The value can be a Decimal or Integer literal or a reference to a column containing numeric values.

## Basic Usage

Column reference example:

derive type:single value:ABS(MyInteger) as:'abs_MyInteger'

Output: Generates the new `abs_MyInteger` column containing the absolute value of each value found in the `MyInteger` column.

Numeric literal example:

delete row:(ABS(MyInteger) == 5)

Output: Deletes all rows from the dataset in which the absolute value of the entry in the `MyInteger` column is 5.

## Syntax and Arguments

derive type:single value:ABS(numeric_value)

ArgumentRequired?Data TypeDescription
numeric_valueYstring, decimal, or integerName of column or Decimal or Integer literal to apply to the function

### numeric_value

Name of the column or numeric literal whose absolute value is to be computed.

• Missing input values generate missing results.
• Literal numeric values should not be quoted. Quoted values are treated as strings.
• Multiple columns and wildcards are not supported.

Usage Notes:

Required?Data TypeExample Value
YesString (column reference) or Integer or Decimal value`-10.5`

## Examples

### Example - Basic ABS function

Source:

Your source data looks like the following, which measures coordinate distances from a fixed point on a grid:

XY
-24
-6.2-2
0-4.2
44
15-0.05

Transform:

You can use the following transform to derive the absolute values of these columns, which now measure distance from the fixed point:

derive type:single value: ABS(X) as: 'distanceX'

derive type:single value: ABS(Y) as: 'distanceY'

Results:

XYdistanceXdistanceY
-2424
-6.2-26.22
0-4.204.2
4444
15-0.05150.05

You can then use POW and `SQRT` functions to compute the total distance.

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